2x^2-5x+32=7

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Solution for 2x^2-5x+32=7 equation: 



2x^2-5x+32=7

We move all terms to the left:

2x^2-5x+32-(7)=0

We add all the numbers together, and all the variables

2x^2-5x+25=0

a = 2; b = -5; c = +25;
Δ = b2-4ac
Δ = -52-4·2·25
Δ = -175
Delta is less than zero, so there is no solution for the equation

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